Hello.
I am doing the exercise on rgb to hex converter, and I have completed all the code, and, afterwards, looked at the hints. Yet when I run, it provides this error:

```
'On line seventeen
def hex_rgb():
^
SyntaxError: invalid syntax
```

Here is the actual code (I have removed the interior of the functions to condense it.

```
def rgb_hex():
def hex_rgb():
def convert():
convert()
```

Thanks!

now we might not be able to find the issue. Donâ€™t condense the code

consider this:

```
print("hello world"
x = 3
```

now i get a syntax error on line 2, while the error is on line 1 (missing closing parentheses)

same is very likely true for your error. But i canâ€™t see that now due to the condensed code.

3 Likes

Not really condensed , is it. More like completely missingâ€¦

1 Like

Here is the full code(in python 2):

```
def rgb_hex():
invalid_msg = 'Incorrect values entered.'
red = int(raw_input('Enter red (R) value:'))
if (red < 0 or red > 255):
print 'Invalid red value.'
return
green = int(raw_input('Enter green (G) value:'))
if (green < 0 or green > 225):
print 'Invalid green value.'
return
blue = int(raw_input('Enter bblue (B) value:'))
if (blue <0 or blue > 225):
print 'Invalid blue value.'
return
val = (red << 16) + (green << 8) + blue
print '%s' % (hex(val)[2:].upper()
def hex_rgb():
hex_val = raw_input('Enter hexadecimal value: ')
if len(hex_val) != 6:
print 'Invalid hexadecimal value entered.'
return
else:
hex_val = int(hex_val, 16)
two_hex_digits = 2 ** 8
blue = hex_val % two_hex_digits
hex_val = hex_val >> 8
green = hex_val % two_hex_digits
hex_val = hex_val >> 8
red = hex_val % two_hex_digits
print 'Red: %s, Green: %s, Blue: %s' % (red, green, blue)
def convert():
while True:
option = raw_input('Enter 1 to convert RGB to HEX. Enter 2 to convert HEX to RGB. Enter X to Exit: ')
if option == '1':
print 'RGB to Hex...'
rgb_hex()
elif option == '2'
print 'Hex to RGB...'
hex_rgb()
elif option == 'x' or option == 'X':
break
else:
print 'Error.'
convert()
```

Is this statement complete?:

```
print '%s' % (hex(val)[2:].upper()
```

It is the final line in the `rgb_hex`

function definition.

1 Like

No, it should have a closing parentheses for the hex function! Thank you very much!

1 Like

I guessed the error correctly:

when dealing with syntax error, always check the line above as well.

4 Likes

system
closed
January 3, 2020, 5:59am
#8
This topic was automatically closed 18 hours after the last reply. New replies are no longer allowed.