Why, ValueError: invalid literal for int() with base 10?

platform_issue
battleship

#1
from random import randint

board = []

for x in range(0, 5):
  board.append(["O"] * 5)

def print_board(board):
  for row in board:
    print " ".join(row)

print_board(board)

def random_row(board):
  return randint(0, len(board) - 1)

def random_col(board):
  return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

# Everything from here on should be in your for loop
# don't forget to properly indent!
for turn in range(4):
  print "Turn", turn + 1
  guess_row = int(raw_input("Guess Row:")) # <------- Line 29
  guess_col = int(raw_input("Guess Col:"))

  if guess_row == ship_row and guess_col == ship_col:
    print "Congratulations! You sank my battleship!"
    break
  else:
    if guess_row not in range(5) or \
      guess_col not in range(5):
      print "Oops, that's not even in the ocean."
    elif board[guess_row][guess_col] == "X":
      print( "You guessed that one already." )
    else:
      print "You missed my battleship!"
      board[guess_row][guess_col] = "X"
    if (turn == 3):
      print "Game Over"
    print_board(board)

Traceback (most recent call last): File “python”, line 29, in
;module>
ValueError: invalid literal for int() with base 10: ‘’

Why?


Why do I get a “break outside of loop” error?
#2

Of late, this has been a recurring problem. From our POV we cannot discern the cause; that will be up to the engineers to track down. What we can suggest is to manually enter two values so the lesson can be completed.

guess_row = ship_row
guess_col = ship_col

or any arbitrary values within range.


#3

Wow, I was at my wits end…