# Why, ValueError: invalid literal for int() with base 10?

#1
``````from random import randint

board = []

for x in range(0, 5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

# Everything from here on should be in your for loop
# don't forget to properly indent!
for turn in range(4):
print "Turn", turn + 1
guess_row = int(raw_input("Guess Row:")) # <------- Line 29
guess_col = int(raw_input("Guess Col:"))

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sank my battleship!"
break
else:
if guess_row not in range(5) or \
guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif board[guess_row][guess_col] == "X":
print( "You guessed that one already." )
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
if (turn == 3):
print "Game Over"
print_board(board)
``````

Traceback (most recent call last): File “python”, line 29, in
;module>
ValueError: invalid literal for int() with base 10: ‘’

Why?

Why do I get a “break outside of loop” error?
#2

Of late, this has been a recurring problem. From our POV we cannot discern the cause; that will be up to the engineers to track down. What we can suggest is to manually enter two values so the lesson can be completed.

``````guess_row = ship_row
guess_col = ship_col
``````

or any arbitrary values within range.

#3

Wow, I was at my wits end…