Why isn't my code printing to the console?

Get Help JavaScript
#1 
const userName = "Melissa";

userName === "Melissa" ? console.log(`Hello ${userName}`)
      : console.log("Hello!");

const userQuestion = "Will I take a lot of computer science classes?";

console.log(`The user asked: ${userQuestion}`);

let randomNumber = Math.floor(Math.random() * 8);
let eightBall = "";

switch(randomNumber){
    
  case "0": 
    console.log("It is certain")
    break;
        
     case "1": 
    console.log("It is decidedly so")
    break;
    
     case "2": 
    console.log("Reply hazy try again")
    break;
    
     case "3": 
    console.log("Cannot predict now")
    break;
    
     case "4": 
    console.log("Do not count on it")
    break;
    
     case "5": 
    console.log("My sources say no")
    break;

     case "6": 
    console.log("Outlook not so good")
    break;
    
     case "7": 
    console.log("Signs point to yes")
    break;
}

Printing:

Hello Melissa
The user asked: Will I take a lot of computer science classes?

As you can see, my console.logs are not printing to the screen.

#2

that very likely means none of the cases are true, we could confirm this by adding a default to see if that is printed

if that is the case (pun intended), something is wrong with the comparisons

#3

Nevermind I figured it out… the value output for my variable is a number, but I had it set to strings… So it wasn’t the same.

1 Like
#4

i know, and i could have told you the answer, but getting there yourself teaches you so much more :slight_smile: Know you had some crucial thinking steps like: Why are my conditions not correct?

#5

Thanks!

It is better when I figure it out myself :slight_smile: I was super happy!

2 Likes