Why is the list I print not filtered?
If you’ve written your filter() code on a line by itself, it will not be printed to the screen. The only way something will be printed is to use the print function.
It’s perfectly fine to print the results of a function by writing that function, like filter() after the word print, like this:
print filter(lambda, list_name)
a=[x*2 for x in range(1,11)]
print(filter(lambda x: x<8,a))
when I run this code in command promt , it return:
<filter object at 0x000000000294E588>
why?
I’m using python -3
Cause python3 is dumb about this stuff, and print() used on objects tries to call __repr__ or __str__ , which they probably don’t have.
Do print(list(lambda x: x<8, a)) since print() can figure out how to print out a list
Edit:
I looked more into it. Basically, its not that python3 is dumb. They intentionally don’t really want you to use filter() and map() to get a list. They recommend using list comprehensions instead now. If you want to still use it this way, you have to manually use list() to turn it into a list.
The decision was made on purpose to use an iterator for things like filter, which is more memory efficient:
Please I have a concern. It’s specified we only print the squares that are between 30 and 70 which are [36,49,64] but an error is diplayed by suggesting me to display 1 to 100. I don’t understand
A link would be forthcoming, we would hope.
>>> q = [x ** 2 for x in range(11)]
>>> for x in filter(lambda x: 30 <= x <= 70, q):
print (x)
36
49
64
>>>