Why is it not printing the updated word?

Frequently Asked Questions Python FAQ
1

Question

Why is it not printing the updated word?

Answer

If you’re still printing the original variable, then you should expect to see the original input string printed to the console. To see the string we’ve made some changes to by now, we need to print the variable we want to see displayed to the screen. For example:

first_string = “My initial STRING!”
new_string = first_string.lower() + “ Altered!”
print first_string

In the code above, we made a string, changed it, but are still printing the first string we made. To see the changed string, we’d print new_string.

1 Like
2

I think there is a bug here, I copy and paste the solution after reseting the lesson and yet it is still showing error/incorrect syntax

3

Please post a link to this exercise so we can have a look.

4

Experiencing the same thing for some reason.

https://www.codecademy.com/courses/learn-python/lessons/pyglatin/exercises/move-it-on-back

5

same here, it is basically impossible!

6

the reason why it isnt working is because you need to actually type "print " and the variable to allow it to show the word in its updated form.

2 Likes
7

https://www.codecademy.com/courses/learn-python/lessons/pyglatin/exercises/move-it-on-back

I have typed print, it’s still not working

8

https://www.codecademy.com/courses/learn-python/lessons/pyglatin/exercises/move-it-on-back
yep this is still not working can someone tell what i can do to fix it?

9

“Traceback (most recent call last):
File “python”, line 3, in
ExecTimeoutException: Program took too long to terminate.”
This is what I have been getting while working in this entire section of PYGLATIN

7 Likes
10

If the program will not accept inputs in the console, then bypass the prompt (comment it out) and assign a literal string to the variable. Then run the program with that.

11

Which of the variables to be specific? And I can’t seem to to get any result on the console prompt if I enter a word, which I’ve tried severally in capital letters. I use google chrome.

12

Any that are associated with prompt() statements. Just write in their values and run the program.

13

Checked it a few times. it seems to bug on the .lower
That leads to
–>Traceback (most recent call last):
File “python”, line 7, in
TypeError: unsupported operand type(s) for +: ‘builtin_function_or_method’ and ‘unicode’

found out there was just a syntax error at my side. in the .lower

14

Okay, just copy and paste this.

pyg = ‘ay’;
original = ‘string’;

if len(original) > 0 and original.isalpha():
word = original.lower();
first = word[0];
new_word = word + first + pyg;
else:
print(‘empty’);

15

pyg = ‘ay’;
original = ‘string’;

if len(original) > 0 and original.isalpha():
word = original.lower();
first = word[0];
new_word = word + first + pyg;
else:
print(‘empty’);

16

For me I was stuck for a bit because every time I would run it it would print the word i did before and not the current one that I just entered. So I fixed it by moving the print to below the rest of the indented code like this (I just put this here for others i case they have the same problem):

pyg = ‘ay’

original = raw_input(‘Enter a word:’)

if len(original) > 0 and original.isalpha():

word = original.lower()

first = word[0]

new_word = word + first + pyg

print new_word

else:

print 'empty'
18

I still cannot get past this prompt. I have tried everything – my roommate who is a data scientist and uses Python every single say also cant figure out whats going on.

19

sometimes, CTRL F5 works

20

When I did this code, is still did show the word that I entered on the console as is, Is this okay?

pyg = ‘ay’

original = raw_input(‘Enter a word:’)

if len(original) > 0 and original.isalpha():
word = original.lower()
first = word[0]
new_word = word + first + pyg
print original
else:
print ‘empty’

21

Hello andrejohnnolivo760318,

Try switching out the print original to print new_word at the end of the if statement. It should change what you typed in the prompt. Also, don’t forget to indent the new variables under the if statement. Hope this helps.

pyg = ‘ay’

original = raw_input(‘Enter a word:’)

if len(original) > 0 and original.isalpha():

word = original.lower()
first = word[0]
new_word = word + first + pyg

print new_word
else:
print ‘empty’