# Why does my code work, with no reference to previous function?

#1

There is no error but I don't understand it.

I print the line: print get_letter_grade(lloyd) but I think there has to be a reference to the previous function get_average. Why is the complier able to use the dictionary ("llyod") as argument for get_letter_grade function which demands a number?

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total=sum(numbers)
total=float(total)

def get_average(student):
homework=average(student["homework"])
quizzes=average(student["quizzes"])
tests=average(student["tests"])
return 0.1*homework+0.3*quizzes+0.6*tests

if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >= 60:
return "D"
else:
return "F"

#2

You shouldn't be able to @h4iti

The purpose of this lesson was to print `get_letter_grade(get_average(lloyd))`.

So, `get_average(lloyd)` returns a number. Interesting issue you got here...

#3

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