Why does my code work, with no reference to previous function?


#1



https://www.codecademy.com/en/courses/python-beginner-en-qzsCL/1/4?curriculum_id=4f89dab3d788890003000096


There is no error but I don't understand it.


I print the line: print get_letter_grade(lloyd) but I think there has to be a reference to the previous function get_average. Why is the complier able to use the dictionary ("llyod") as argument for get_letter_grade function which demands a number?


lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!
def average(numbers):
    total=sum(numbers)
    total=float(total)
    return total/len(numbers)
    
def get_average(student):
    homework=average(student["homework"])
    quizzes=average(student["quizzes"])
    tests=average(student["tests"])
    return 0.1*homework+0.3*quizzes+0.6*tests
    
def get_letter_grade(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

print get_letter_grade(lloyd)


#2

You shouldn't be able to @h4iti

The purpose of this lesson was to print get_letter_grade(get_average(lloyd)).

So, get_average(lloyd) returns a number. Interesting issue you got here...


#3

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