Why does console.log (compare(userChoice, computerChoice)); print


#1

I completed the code and it works perfectly.

It took me a while to figure out how to "print" the result.... i.e. "paper wins" or whatever it might be.

I know that if I use this code below works
console.log (compare(userChoice, computerChoice));

but why doesn't this code work for printing the result
console.log (compare);

If "compare" is the variable and it is defined by the function that follows, why won't it print?

I hope this question makes sense to someone.

here is the whole code....

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34)
{computerChoice = "rock";}
else if(computerChoice <= 0.67)
{computerChoice = "paper";}
else
{computerChoice = "scissors"}
console.log("Computer: " + computerChoice);
var compare = function (userChoice, computerChoice)
{if (userChoice === computerChoice)
{return "The result is a tie!"}
else if (userChoice === "rock")
{if (computerChoice === "scissors")
{return "rock wins";}
else
{return "paper wins";}
}
else if (userChoice === "paper")
{if (computerChoice === "rock")
{return "paper wins";}
else
{return "scissors wins";}
}
else if (userChoice === "scissors")
{if (computerChoice === "paper")
{return "scissors wins";}
else
{return "rock wins";}
}
}
console.log (compare(userChoice, computerChoice));

Thanks


#2

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on

  • the execution of the compare-function

#3

+++ function talk

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );