# Why do I keep getting a syntax error?

#1
``````def fizz_count(x):
count= 0
for x in fizz_count(x):
if x = 'fizz':
count= count + 1
print count``````

I keep getting a syntax error for the `if x = 'fizz'` this am I suppose to write down the whole function or is it a problem with the fizz part I already tried `if x = 'fizz':` , `if x = "fizz":` and `if x = fizz:` I don't what to use I thought it was `"fizz"` because it was from a list value but I am not sure?

#2

def fizz_count(x):
count=0
for item in x:
if item == 'fizz':
count=count+1
return count

# Good luck coding!

#3

Hi @bob1352,

You are using the `=` assignment operator. What you want to use is the `==` equality operator instead

Here's the gist of it:

``````# Try reading this as 'x is now 12'
x = 12
# printing x will confirm this:
print x

# Reassigning a new value to x like so
x = 10
# and printing it will confirm that using the = assignment
# operator changes the value of x
print x

# Now try reading this as `x is it 10?`
x == 10
# printing it will confirm that it is
print x == 10    # yields true

# printing this will also confirm that it is not 12
# and that using the equality operator == does not change the value of x
print x == 12    # yields false``````

So you just need to change your operator in the condition of your `if` and as @indianmuffin mentioned, use `return` instead of `print` and you should be on your way...

Good luck!

#4

This is the correct answer. It worked for me. Please see my code below:

``````def fizz_count(x):
count = 0
for word in x:
if word == 'fizz':
count = count + 1
return count

list_1 = ['fizz', 'crap', 'fizz', 'stuck', 'hate', 'fizz', 'damn', 'buzz', 'fizz']
fizz_list = fizz_count(list_1)
print fizz_list``````

#5

Hi @ninagt3,

See this other thread to learn the trick and have the code you paste retain indentation and formatting...

#6

You used the for loop wrong.

your function is acting on the argument/ list called x

and what you want is for each piece of data in the list x, if the piece of data is equal to the string 'fizz', add 1 to the amount of times fizz has been counted

so it would look like:

for piece_of_data in x:
if piece_of_data == 'fizz':
count += 1 #the correct shorthand for adding something to a variable is +=
return count

try that and tell e how it works,.... also, replace piece_of_data to the word item