Why did it print out when i didn't use console.log


#1


https://www.codecademy.com/en/courses/javascript-beginner-en-Bthev-mskY8/1/4?curriculum_id=506324b3a7dffd00020bf661

It behaves correctly


var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
	computerChoice = "rock";
} else if(computerChoice <= 0.67) {
	computerChoice = "paper";
} else {
	computerChoice = "scissors";
} console.log("Computer: " + computerChoice);

var compare = function(choice1, choice2) {
    if (choice1 === choice2) {
        return "The result is a tie!";
    }
 else if (choice1 === "rock") {
    if (choice2 === "scissors") {
        return "rock wins";
    } else {
        return "paper wins";
    }
}
 else if (choice1 === "paper") {
     if (choice2 === "rock") {
         return "paper wins";
     } else {
         return "scissors wins";
     }
 }
  else if (choice1 === "scissors") {
      if (choice2 === "rock") {
          return "rock wins";
      } else {
          return "scissors wins";
      }
  }

}

compare(userChoice, computerChoice);

output: Computer: paper
"paper wins"

Why did "paper wins" print out when I didn't use console.log?

Thank you!


#2

You are declaring userChoice and computerChoice strings such as "paper wins".

So when you call the function compare at the bottom you print out the string.


#3

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