What's wrong here?


#1

var isEven = function(number) {
return true;
};
if (isEven(4)/ 2 === 2) {

} 
else {

 }

i need write an if / else statement inside the isEven function. It should return true; if the number it receives is evenly divisible by 2. Otherwise (else), it should return false;.


#2

@betaace01730,

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );

#3

@betaace01730,
Javascript has the so-called Remainder-operator %
is actually a modulo-operator
and if used it will return the rest-value.

9%3 You read it as nine modulo three is zero, as 9 divided by 3 has NO rest-value.
22%6 You read 22 modulo six is 4, as 22 divided by 6 will leave you with rest-value 4
10%5 You read 10 nodulo five is zero, as 10 divided by 5 will have NO rest-value

In this section you have to figure out
if some number is divisible by 2 with NO-Rest-value.....
number%3=2 You read it as number modulo two is zero, as number divided by 2 has NO rest-value.

You will have to use an IF ELSE-statement
with a condition ( number % 2 === 0)
.

google search
== the Book ==
javascript remainder operator site:developer.mozilla.org
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators

== discussions / opinions ==
javascript remainder operator site:stackoverflow.com
http://stackoverflow.com/questions/4467539/javascript-modulo-not-behaving

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comparison_Operators
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Expressions_and_Operators

== guidance ==
www.crockford.com
http://javascript.crockford.com/survey.html
http://javascript.crockford.com/code.html <<< Javascript coding conventions