What if choice1 is scissors?


#1



I keeping getting an error that my result keeping showing "paper wins" when my inputs are scissors and rock.


 
var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
	computerChoice = "rock";
} else if(computerChoice <= 0.67) {
	computerChoice = "paper";
} else {
	computerChoice = "scissors";
} console.log("Computer: " + computerChoice);
 var compare = function (choice1, choice2) {
     if(choice1 === choice2) {
         return "The result is a tie!";
     }
     else if (choice2 === "scissors") {
         return "rock wins";
     }
       else {
         return "paper wins";
     }
     if (choice1 === choice2) {
         return "The result is a tie!";
     }
     else if (choice1 === 'paper') {
         if (choice2 === 'rock') { 
             return 'paper wins';
         }
         else {
             return "scissors wins";
         }
     }
     if (choice1 === choice2) {
         return "The result is a tie!";
     }
     else if (choice1 === "scissors") {
         if (choice2 === "rock") {
             return "rock wins";
         }
         else {
             return "scissors wins";
         }
     }
 }
compare(userChoice, computerChoice);


#2

@nazibkhan1234,

Your IF ELSE-IF IF ELSE statement structure is not correct

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )