What if choice1 is scissors? I don't understand what is wrong


#1


https://www.codecademy.com/en/courses/javascript-beginner-en-Bthev-mskY8/1/4?curriculum_id=506324b3a7dffd00020bf661#

"SyntaxError: expected expression, got keyword 'else' "

Get this every time, I've gathered that means an else statement is not properly curly bracketed(right?) but I'm just not seeing it and it's driving me insane.


var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
	computerChoice = "rock";
} else if(computerChoice <= 0.67) {
	computerChoice = "paper";
} else {
	computerChoice = "scissors";
} console.log("Computer: " + computerChoice);

var compare = function(choice1, choice2) {
if (choice1 === choice2) { 
    return "The result is a tie!";
    }
else if (choice1 === "rock") {
    if (choice2 === "scissors") {
        return "rock wins"; 
    }
    else { 
        return "paper wins"; 
    }
    
}
else if (choice1 === "paper") {
    }
    if (choice2 === "rock") {
        return "paper wins";
    }
    else {
        return "scissors wins";
    }
else if (choice1 === "scissors") {
   }
    if (choice2 === "rock") {
        return "rock wins"; 
     }
     else {
         return "scissors wins";
     }
}


console.log(compare(userChoice, computerChoice));


#2

This post was flagged by the community and is temporarily hidden.


#3

Ugh dammit, of course it would be something right in front of my face that I missed. Thanks!