What if choice1 is rock?


#1

Continuing the discussion from Archive of QA for this lesson:
I have no Idea what is wrong with this but it keeps popping up with an error for the syntax. I have redone this thing about 5 times!! HELP!!


var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
	computerChoice = "rock";
} else if(computerChoice <= 0.67) {
	computerChoice = "paper";
} else {
	computerChoice = "scissors";

var compare = function(choice1, choice2) {
if (choice1 === choice2) {
    return "The result is a tie!";
    }
else if (choice1 === "rock") {
    if (choice2 === "scissors") {
    return "rock wins";
    }
    else {
        return "paper wins";
    }
}

        else if (choice1 === "paper") {
                if (choice2 === "rock") {
                    return "paper wins";
                } 
                else {
                    return "scissors wins";
                }
            }
            };


#2

else {
    computerChoice = "scissors";
/* missing } */
var compare = function(choice1, choice2) {

see comment in code, your else is missing its closing curly bracket


#3

I tried this but it is still showing an error.


#4

please post an updated version of your code