What if Choice1 is rock? Something is wrong here


#1

This is my program so far.

/*var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = "rock";
} else if(computerChoice <= 0.67) {
computerChoice = "paper";
} else {
computerChoice = "scissors";
} console.log("Computer: " + computerChoice);*/
var compare = function(choice1, choice2) {
if (choice1===choice2) {
return "The result is a tie!"
}
else if(choice1 === "rock") {
if(choice2 === "scissors") {
return "rock wins";
}
else{
return "paper wins";
}
};

And with this I get this message "SyntaxError: Unexpected end of input"
What's wrong with it?


#2

@loganbf,

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )