What if choice1 is paper


#1



I keep getting SyntaxError: Unexpected token else. I've been looking and looking and can't figure out whats wrong.


var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
    computerChoice = "rock";
} else if (computerChoice <= 0.67) {
    computerChoice = "paper";
} else {
    computerChoice = "scissors";
}
console.log("Computer: " + computerChoice);
var compare = function(choice1, choice2) {
        if (choice1 === choice2) {
            return "The result is a tie!";
        } else if (choice1 === "rock") {
            if (choice2 === "scissors") {
                return "rock wins";
            } else {
                return "paper wins";
            } else if (choice1 === "paper") {
                if (choice2 === "rock") {
                    return "paper wins";
                } else {
                    return "scissors wins";
                }

            }
    };


#2

@hannahrose1492,
You are forgetting to close the ELSE-IF code-block

else if (choice1 === "rock") {
        if(choice2 === "scissors") {
            return "rock wins";
        }
        else {
            return "paper wins"; 
        }
} //<<<=== you are forgetting to close the ELSE-IF

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )