What if choice1 is paper? Part 7/9


#1

I don't know what I have done that is wrong and keep getting 'SyntaxError: Unexpected token else'
Here is my code:

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34)
{
	computerChoice = "rock";
} 
else if(computerChoice <= 0.67) 
{
	computerChoice = "paper";
} 
else 
{
	computerChoice = "scissors";
} 
console.log("Computer: " + computerChoice);


var compare = function(choice1,choice2)
{
    if(choice1 === choice2)
{
    return("The result is a tie!")
}
else if(choice1 === "rock")
{
    if(choice2 === "scissors")
{
    return "rock wins"
}
}
else
{
    return "paper wins"
}
else if(choice1 === "paper")
{
    if(choice2 === "rock")
{
    return "paper wins"
}
    else
{
    return "scissors wins"
};

#2

    else if(choice1 === "rock")
    {
        if(choice2 === "scissors")
    {
        return "rock wins"
    }
    }
    else
    {
        return "paper wins"
    }

if you give this some formatting (no changes applied):

else if (choice1 === "rock") {
    if (choice2 === "scissors") {
        return "rock wins"
    }
} else {
    return "paper wins"
}

you can see that the else is an alternative to the else if where it should be part of the else if and be an alternative for the if.


#3

That didn't seem to fix the issue, I am still getting the 'Unexpected token else'


#4

never mind, the problem was a misplaced curly bracket, thank you for your help though!