# What if choice 1 = paper?

#1

"unexpected token else" These curly braces are killing me!! Ugh.. I don't think I understand how many are required, and where exactly they go/don't go....

``````var compare = function(choice1, choice2) {
if (choice1 === choice2){
return "The result is a tie!";
}

else if(choice1 === "rock") {

if (choice2 === "scissors"){
return "rock wins";
}
else {
return "paper wins";
}
else if(choice1 === "paper") {
if(choice2 === "rock"){
return "paper wins";
else {
return "scissors wins";
}
}
}
}``````

#2

I got it. Still not exactly sure what I changed to make it correct, but I'm gonna look it over and see exactly where the difference lies. (EDIT: I realize I did not close out the paper wins; with a { after it. And previously had 4 curly braces at the end, where I only needed three. I'm glad I actually figured it out rather than just tweaking and moving curly braces around randomly. I hope this helps someone else who gets stuck on this exercise.

else if(choice1 === "paper") {
if(choice2 === "rock") {
return "paper wins";
}
else {
return "scissors wins";
}
}
}

#3

``````var compare = function(choice1, choice2) { // curly 1a
if (choice1 === choice2) { // curly 2a
return "The result is a tie!";
} // curly 2b
else if(choice1 === "rock") { // curly 3a
if (choice2 === "scissors") { // curly 4a
return "rock wins";
} // curly 4b
else { // curly 5a
return "paper wins";
} // curly 5b
else if(choice1 === "paper") { // curly 6a
if(choice2 === "rock") { // curly 7a
return "paper wins";
else { // curly 8a
return "scissors wins";
} // curly 8b
} // curly 6b
} // curly ?
} // curly ?

// counting our curly brackets
/*
1a
2a2b
3a
4a4b
5a5b
6a6b
7a
8a8b
*/``````

This is my conclusion assigning each of your curly's id's in order of occurence and matching that occurence with a matching closing pair. You can take it from here.

Build Rock, Paper, Scissors... 7. What if Choice 1 = paper
#4

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