What if choice 1 is paper


#1

I cannot figure out what is wrong with my code.
Please help...

var compare = function (choice1, choice2)

{
if (choice1 === choice2) {return ("The result is a tie!");}

else if (choice1 === "rock")  {if (choice2 === "scissors") return ("rock wins!");}

else {return ("paper wins!");}

else if (choice1 === "paper") {if (choice2 === "rock") return ("paper wins!");}

else {return ("scissors wins!");}

};


#2

@js10000,
The way you are writing your IF ELSE-IF statement
is confusing....

Please read the code-convention (as a help)
http://javascript.crockford.com/code.html
AND
Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )