What if choice 1 is paper HELP!


#1

<PLEASE USE THE FOLLOWING TEMPLATE TO HELP YOU CREATE A GREAT POST!>

<Below this line, add a link to the EXACT exercise that you are stuck at.>

<In what way does your code behave incorrectly? Include ALL error messages.>

```

/var userChoice = prompt(“Do you choose rock, paper or scissors?”);
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = “rock”;
} else if(computerChoice <= 0.67) {
computerChoice = “paper”;
} else {
computerChoice = “scissors”;
} console.log("Computer: " + computerChoice);
/
var compare = function(choice1, choice2) {
if(choice1 === choice2) {
return “The result is a tie!”;
}
else if(choice1 === “rock”) {
if(choice2 === “scissors”) {
return “rock wins”;
}
else {
return “paper wins”;
}
}
}
else if(choice1 === “paper”) {
if(choice2 === “rock”) {
return “paper wins”;
}
else {
return “scissors wins”;
}
}
}

it says: “SyntaxError: Unexpected Token else”
and:
“Oops, Try again. There was a problem with your syntax”

<do not remove the three backticks above>

#2

@heammawihio,
With

var compare = function(choice1, choice2) {
    if(choice1 === choice2) {
        return "The result is a tie!";
    }
    else if(choice1 === "rock") {
        if(choice2 === "scissors") {
            return "rock wins";
        }
        else {
            return "paper wins";
        }
    }
} //<<< this closes the =compare= function !!!!

You have already closed the compare Function !!!


#3

Thank you I have been stuck on this for a month and a half! It is weird it said that was right before and now it’s wrong!?:confused: Thank you!


#4

@heammawihio,

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )

#5

Stuck and braindead - please enlighten me!!

var compare = function(choice1,choice2) {
if (choice1 === choice2) {
if (choice1 === “paper”){
return(“The result is a tie!”);
}

if(choice1 === “rock”) {
if(choice2 === “scissors”) {
alert(“rock wins”);
} else {
alert(“paper wins”);
}
}
if(choice1 === “paper”) {
if(choice2 === “rock”) {
alert(“paper wins”);
} else {
if(choice2 === “scissors”) {
alert(“scissors wins”);
}
}
if(choice1 === “scissors”) {
if(choice2 === “rock”) {
alert(“rock wins”);
} else {
if(choice2 === “paper”) {
alert(“scissors wins”);
}
}
}
}
};


#6

@selmadelgado,

:flashlight: :bulb: :sos: :yin_yang:

-1
You are required to use an IF ELSE IF statement structure
Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )

( please be aware you are required to use the return statement )