I am kindly asking to help me with the implementation of each line. Thank you very much.

sum = 0

for x in range(1000):

if str(x) == str(x)[::-1]:

sum += x ** 2

print(sum)

I am kindly asking to help me with the implementation of each line. Thank you very much.

sum = 0

for x in range(1000):

if str(x) == str(x)[::-1]:

sum += x ** 2

print(sum)

for all the numbers from 0 to 1000

if, for that number, the number forward is the same as the number backward,

add the square of that number to the sum.

[The square of a number is the number times itself, or the number to the 2nd power.]

(So you get the sum of the squares of the numbers, between 0 and 1000, using only the numbers that are the same as the number written in reverse.)

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Thank you very much.