Using a for loop with a float

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1

When using a for loop, for example:

    def num_count(x):
        for numbers in x:

if “numbers” is not always an integer, perhaps a float, how do you get by this? It throws an error.

is the only proper way to do this?

def num_count(x):
    numbers = (int(x))
    for i in numbers:
2

@xyphoris,

import math
def num_count(numbers):
    print "floor\t  int\t  i\t ceil"
    print "=====\t=====\t=====\t====="
    for i in numbers:
        print "{0}\t{1}\t{2}\t{3}".format(
               math.floor(i),int(i),i,math.ceil(i))

num_count([0.12,1.6,1.4,-3.6])

gives the [output]

floor	 int	  i	ceil
=====	=====	=====	=====
0.0	0	0.12	1.0
1.0	1	1.6	2.0
1.0	1	1.4	2.0
-4.0	-4	-3.6	-3.0

http://stackoverflow.com/questions/31036098/what-is-the-difference-between-int-and-floor-in-python-3