Unexpected output


#1

Hello

For the 13. Not Again! exercise in Battleship! with the following code:

from random import randint 

board = [] 

for x in range(0, 5):
    board.append(["O"] * 5) 

def print_board(board):
    for row in board:
        print " ".join(row) 

print_board(board) 

def random_row(board):
    return randint(0, len(board) - 1) 

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board) 
ship_col = random_col(board) 
guess_row = int(raw_input("Guess Row:")) 
guess_col = int(raw_input("Guess Col:"))

print ship_row 
print ship_col 

# Write your code below!

if guess_row == ship_row and guess_col == ship_col:
    print("Congratulations! You sank my battleship!")
elif board[ship_row][ship_col] == "X":
    print("You guessed that one already.")
elif guess_row != range(5) or guess_col != range(5):
    print("Oops, that's not even in the ocean.")
else:
    print("You missed my battleship!")
    board[guess_row][guess_col] = "X"
    print_board(board)

I am getting the following output:

O O O O O
O O O O O
O O O O O
O O O O O
O O O O O
Guess Row: 3
Guess Col: 2
4
0
Oops, that's not even in the ocean.
None

I can't figure out why the 2nd elif condition is being triggered instead of the else condition


#2

well, range() produces a list as output, guess_row is an integer. an integer doesn't equal a list, so the condition is true, so the code prints that the guess is not in the ocean


#3

Thanks a lot stetim !

And I also wasn't using "not in" boolean expression... So it wouldn't have worked either way.. I need to start reading things closer


#4

that was my point exactly, != won't work, like you discovered you need to use not in


#5