please kindly help advise , under the function def nth_last_node , since we defined current = None , to my understanding , since i dont see there is no anyother code about “current” , so current will be always “None”. so the else will never be executed since “if current is None” will always be executed.

```
from LinkedList import LinkedList
# Complete this function:
def nth_last_node(linked_list, n):
current = None
tail_seeker = linked_list.head_node
count = 1
while tail_seeker:
tail_seeker = tail_seeker.get_next_node()
count += 1
if count >= n + 1:
if current is None:
current = linked_list.head_node
else:
current = current.get_next_node()
return current
def generate_test_linked_list():
linked_list = LinkedList()
for i in range(50, 0, -1):
linked_list.insert_beginning(i)
return linked_list
# Use this to test your code:
test_list = generate_test_linked_list()
print(test_list.stringify_list())
nth_last = nth_last_node(test_list, 4)
print(nth_last.value)
```