This is based of the LEARN C Mini-Calendar Project
=====================x==========================
In my program, I am asking the user to input a date(in just integers ie 12 31 2019 367) and the number of days they add to it. In one of my functions, this is precisely what I am doing.
The user inputs 12 31 2019 367, and the program is meant to print 1 1 2021, but instead prints 1 1 2020(a year behind)…
What I did(Sorry for a lot of code, I tried to keep it simple and clean):
int days_in_month[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
void add_days_to_date(int *mm, int *dd, int *yy, int days_left_to_add)
{
int days_left_in_month;
while(days_left_in_month > 0)
{
days_left_in_month = days_in_month[*mm] - *dd;
// days_left_in_month = days_in_month[*mm] - *dd;
if (days_in_month[2] && is_leap_year(*yy) == true)
{
days_left_in_month++;
}
} // end while
printf("after while\n");
if(days_left_to_add > days_left_in_month)
{
days_left_to_add -= days_left_in_month;
*dd = 1;
if(*mm == 12)
{
*mm = 1;
(*yy)++;
}
else
{
(*mm)++;
}
}
else
{
*dd += days_left_to_add;
days_left_to_add = 0;
}
}
int main()
{
int mm, dd, yy, days_left_to_add;
printf("Please enter a date between the years 1800 and 10000 in the format mm dd yy and provide the number of days to add to this date:\n");
scanf("%d %d %d %d", &mm, &dd, &yy, &days_left_to_add);
// printf("\nREAD\n");
//These are pointers, so they have to be at certain location i.e. int* mm = &mm
add_days_to_date(&mm, &dd, &yy, days_left_to_add);
printf("%d %d %d\n", mm, dd, yy);
}
What I got after inputs:
Inputs: 12 31 2019 367
Output: 1 1 2020(meant to be 1 1 2021)
Thank you in advance and for your time and patience…