# Write your in_range function here:

def in_range(num, lower, upper):
if (num == range(lower, upper)):
return True
else:
return False

# Uncomment these function calls to test your in_range function:

print(in_range(10, 10, 10))

# should print True

print(in_range(5, 10, 20))

# should print False

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Create a function named `in_range()` that has three parameters named `num`, `lower`, and `upper`.

The function should return `True` if `num` is greater than or equal to `lower` and less than or equal to `upper`.

Otherwise, return `False`.

`range` will create an immutable sequence of numbers.
`num` is a number.

``````if (num == range(lower, upper)):
``````

A number is not equal to a sequence of numbers, so the if condition will evaluate to `False`

Try to figure out a condition which will meet the specifications of the challenge.

I think the issue is that you are creating a sequence of numbers in the range() function and you can’t compare one value to this because it will always return false because it would not match your num parameter which is only one value.

range(5, 8) = range(5,8)
list(range(5, 8)) = [5, 6, 7]

If you are trying to compare num to see if it is equal either lower or upper, you could use an “or” statement in your function which can check if one of the conditions are met. You would just have to set the conditional statement twice like this:

if (x==a) or (x==b): # paranthesis there for clarity
return True
else:
return False