The Next if method is really tough for me can anyone help me?

#1

Add a line to your loop before your print statement. Use the next keyword so that you skip to the next iteration if the number i is odd.

Use the example above for help, but remember that the example above skips even numbers.

So heres the example it gave.....for i in 1..5
next if i % 2 == 0
print i
end

Here was my answer....i = 18
loop do
i -= 1
next if i % 3 == 0
print "#{i}"
break if i == 0
end....

Its not skipping the odd numbers can anyone help me?

#2

The module(%) tests for remainders. use `i % 2 == 0` instead of `i % 3 == 0`. If you wanted to capture an odd number you would use `i % 2 == 1`.

I'm not that familiar with the ruby syntax but I hope that fixes your problem.

#3

Hi edwin thanks for the response i tried what you told me an it tells me this "It looks like your loop doesn't print out the numbers 18 to 0."

#4

``````i = 18
loop do
if i % 2 == 0
print "#{i}"
i -= 1
else
i -= 1
break if i == 0
end
end``````

Here is what I came up with. It may have wanted you to print out 18 as well.. With your program the first number printed would be 16 since `i` is subtracted one immediately before the if operation is done. Hope it works .

Oh, and if it wants the 0 to be printed too, just change `break if i == 0` to `break if i < 0`