# Make sure that the_flying_circus() returns True def the_flying_circus(): if 4**2 == (8 * 2): print Success elif 1 == 1 print Success again else (10 + 10) > (2 + 5): print Triple Success
i think the indention error is cause by the missing colon at the end of your elif statement, that should solve your current issue. If a new issue arise, please try to solve it yourself first, before posting here. If you get stuck again in this exercise, you can post in this topic again, i will help you
if something: # code elif something else: # code else: # no conditional on else
When printing text, it must be in quotes.
This is moot, though, since it is not what has been asked for. Just make sure your function returns True.
if 4**2 == (8 * 2):
elif 1 == 1:
print Success again
else (10 + 10) > (2 + 5):
print Triple Success
So I corrected the colon, but it says there is a syntax error on line 6
def the_flying_circus(): if 4**2 == (8 * 2): print "Success" elif 1 == 1: print "Success again" else (10 + 10) > (2 + 5): print "Triple Success"
I fixed the colon, but there is a syntax error on line 7
else can't have a condition, since it is everything else. And you are still not return True, like the exercises asks of you