# The Big If (Can't find the bug)

#1

def the_flying_circus():
if 7>6: # Start coding here!
print "That is true!"
elif (3 > 2) and (5 == 5):
print "This is false!"
# You'll want to add the else statement, too!
else this_is_true():
print "This is true!"

File "python", line 8
else this_is_true():
^
SyntaxError: invalid syntax

#2
``````def the_flying_circus():
if 7>6: # Start coding here!
print "That is true!"
elif (3 > 2) and (5 == 5):
print "This is false!"
# You'll want to add the else statement, too!
else:  # this_is_true():
print "This is true!"

the_flying_circus()``````

#3

Thanks Leo for the bug fix!

#4

script.py

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# Make sure that the_flying_circus() returns True

def the_flying_circus():
if 7>6: # Start coding here!
print "That is true!"
elif (3 > 2) and (5 == 5):
print "This is false!"
# You'll want to add the else statement, too!
else: # this_is_true():
print "This is true!"
the_flying_circus()

File "python", line 12
SyntaxError: 'return' outside function

what is wrong with me here @leonhard.wettengmx.n

#5

@leonhard.wettengmx.how do i add a return statement here

#6

``````def the_flying_circus():
if 7>6: # Start coding here!
print "That is true!"
return True
elif (3 > 2) and (5 == 5):
print "This is false!"
# You'll want to add the else statement, too!
else: # this_is_true():
print "This is true!"

the_flying_circus()
#or also displaying the =return= VALUE
print the_flying_circus()``````

### the FUNCTION talk

``````def myFunc( param1, param2):
# Begin of =myFunc= FUNCTION-BODY
# this =myFunc= function- has 2 PARAMETERS param1 and param2
# param1 and param2 PARAMETERS are used
# as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
print( param1 + " and " + param2 )
#End of =myFunc= FUNCTION-BODY``````

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren")

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

``````def myFunction( param1 ):
# //Begin of =myFunction= FUNCTION-BODY
# //=myFunction= function has 1 PARAMETER param1
# //this param1 PARAMETER is used as a -local- VARIABLE
# //throughout the =myFunction= FUNCTION-BODY
return param1;
# //End of FUNCTION-BODY``````

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 )

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

#### ============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

``````theResult = myFunction( 4 )
print theResult``````

OR directly

``print myFunction( 4 )``