The average for alice comes wrong!


#1



lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

#students = [lloyd, alice, tyler]

# Add your function below!
def average(numbers):
    total = sum(numbers)
    total= float(total)
    result = total / len(numbers)
    return result
   
def get_average(student):
    homework = average(student["homework"])
    quizzes = average(student["quizzes"])
    tests = average(student["tests"])
    return 0.1*homework + 0.3*quizzes + 0.6*tests

def get_letter_grade(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"
    
def get_class_average(student):
    results = []
    
    for student in students:
        results.append(get_average(student))
    return average(results)


#2

Hello @sandhue,
Can you post the link of the exercise?

Also..

The average for alice comes wrong!

We can't pass alice (It's a dictionary) to our average() function,
The design of function is so that it deals list with numbers as items.


#3

https://www.codecademy.com/courses/python-beginner-en-qzsCL/1/4?curriculum_id=4f89dab3d788890003000096


#4

Turns out to be a typo, check your get_class_average() function's parameter!


#5

ohhh yeahh... thank u..


#6

what is the solution im stuck too?


#7

If you post your code here or as a new post, we can help debugging it.
Asking for answers is against Guidelines of CC.

check this for creating posts.


#8

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