Test run


#1



https://www.codecademy.com/courses/python-beginner-en-4XuFm/1/5?curriculum_id=4f89dab3d788890003000096


Traceback (most recent call last):
File "python", line 26, in
ValueError: invalid literal for int() with base 10: ''


I would like to understand if i can deal with the user not giving any input


from random import randint

board = []

for x in range(0, 5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

print_board(board)

def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)

print ship_row
print ship_col

guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))

# Write your code below!
if guess_row == ship_row and guess_col == ship_col:
    print"Congratulations! You sank my battleship!"
elif guess_row not in range(5) or \
    guess_col not in range(5):
        print "Oops, that's not even in the ocean."
elif board[guess_row] == "X" or board[guess_col] == "X" :
    print "You guessed that one already."
else:
    board[guess_row][guess_col] = "X"
    print_board(board)
    print "You missed my battleship!"


#2

I'm not sure if you've covered loops yet, but you could make a loop that asks for input and breaks if the input is an int between 1 and 5.


#3

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