Test Run: String


#1



https://www.codecademy.com/en/courses/python-beginner-en-4XuFm/1/5?curriculum_id=4f89dab3d788890003000096


Hi, I would like to get tips on dealing with a user that enters a string rather than integer. Thanks.


from random import randint

board = []

for x in range(0, 5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

print_board(board)

def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))

print ship_row
print ship_col

# Write your code below!
if guess_row == ship_row and guess_col == ship_col:
    print "Congratulations! You sank my battleship!"
else:
    if guess_row not in range(5) or guess_col not in range(5):
        print "Oops, that's not even in the ocean."
    elif board[int(guess_row)] [int(guess_col)] == "X":
            print "You guessed that one already."
    else:
        print "You missed my battleship!"
        board[int(guess_row)] [int(guess_col)] = "X"
    print_board(board)


#2

How would that be efficient? You would have to have every single way they could have possibly written the string in an if, elif statement(s). The slightest grammatical error/sentence structure would give an error.


#3

Well what I"m wondering is if there is a 'if not integer, ask user to input again' so you wouldn't even have to list all the permutations with strings.


#4

Regardless what you are wondering, best be racing through this track. It is about to disappear.


#5

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