synthaxError: 'return' outside function


#1

In the Hint section it says I should use return instead of print but then I got the following problem.
"syntaxError: 'return' outside function.
My question is what does it mean when I get this error, I tried to import it as I was thought that earlier in the Section. Help would be appreciated.

from python import *
def shut_down(s):
    return s
if shut_down() == yes :
    return s("Shutting down")
elif shut_down() == no :
    return ("Shutdown aborted")
else:
    return ("Sorry")

`


Reveiw functions
#2

return is a keyword which is standard included, you don't have to import it.

How to say this nicely? This code is a bit of a mess. look at this simple function:

def example(s):
   print s
example("how parameters work")

s is the function parameter, it will hold the value you pass when calling the function (in this case the string: how parameters work)

so you need to compare s with "yes" and "no"

also, a function ends the moment a return keyword is reached.

one more thing, you can nest an if condition inside a function:

def example():
   if True:
      print "nested if condition inside function"

your if condition is outside the function, which means the return keyword is outside the functions, return keyword can only be used inside functions


#3

return is used to terminate the execution of the function and to return value. Let's say that we have a function square, now we can do something like this:

x = square(2) + square(4)

and after executing the square function value of x will be determined as:

x = 4 + 16 = 20

This means that you can use return only inside functions. Indentation levels are important:

def square(n):
	return n * n # <- inside function
x = square(2) + square(4) # <- outside function

You don't have to import return :slight_smile:


#4

Thank you for the reply very helpful.


#5

This topic was automatically closed 7 days after the last reply. New replies are no longer allowed.