This is not valid JavaScript...

There are no 'man in the middle' comparison expressions in JS. only two binaries.

`0.34 >= computerChoice && computerChoice <= 0.66`

This is still not correct, but it is dialing in. The main point so far is that we have two expressions, each with two operands. The next step will deal with the *truthiness* of the expressions. Do they make sense and are they true?

The above will only work if computerChoice is less than 0.34, in which case it is also less than or equal to 0.66. The segment it is matching is the 0.01 that the first conditional missed.

We're turning this into logic soup when we could be creating order. A lower bound and an upper bound suggests order. Why not impose that on our logic? It simplifies everything.

```
// let c = computerChoice for brevity
var a, b, c = computerChoice;
a = 1 / 3;
b = 2 / 3;
if (c < a) {
//
} else
if (c < b) {
//
} else {
//
}
computerChoice = c;
```