# SyntaxError : invalid syntax

#1

It gives me this error : "SyntaxError : invalid syntax" at line 19

I expect elif to run.

``````"""This program is a calculator that will compute the area of a given shape, as selected by the user. The calculator can determine that area of circles and triangles."""
from math import pi
from time import sleep
from datetime import datetime
now = datetime.now()
print "The calculator is starting up."
print '%s/%s/%s %s:%s' % (now.month, now.day, now.year, now.hour, now.minute)
sleep(1)
hint = "Don't forget to include the correct units!"
print "Enter C for Circle or T for Triangle: "
option = raw_input("Enter C for Circle or T for Triangle: ")
option = option.upper()
if option == 'C':
area = (radius ** 2) * pi
print "The pie is baking. . . "
sleep (1)
print ("Area: %.2f. \n%s" % (area, hint))
elif option == 'T':
base = float(raw_input("Input a base: "))
height = float(raw_input("Input a height: "))
area = base * height
print "Uni Bi Tri. . . "
sleep (1)
print ("Area: %.2f. \n%s" % (area, hint))
else:
print "Invalid input. Terminating program. . . "
sleep(2)
quit()``````

#2

Hi
The reason why python is not happy with your `elif` is because the previous line is not indented. Thus the opening `if` is implicitly closed and that 's why there is an error with the `elif`. The same problem occurs at line 26 with the `else`.

By the way, the surface of a triangle is base * height / 2

Cheerio

#3

Hello,

when I run my code I obtain:

\$ python AreaCalculator.py
File "AreaCalculator.py", line 19
print ("Area: %.2f. \n%s" % (area,hint))
^
IndentationError: unexpected indent

My line 19 is the print() before the elif. I don't understand what is wrong since the print is properly indented.

``````if option == 'C':