# Syntax Error

#1

I'm sure it is simple but I can't quite figure it out.

#2

Your conditions are incorrect here. Remember that `Math.random();` will not generate a number lower than `0`, so there is no need to require `computerChoice` to be greater than `0`.

The condition should simply be:

``````computerChoice <= .33
computerChoice <= .67``````

**Also, using the word `and` in your condition is not a valid operator. You will see how to achieve something similar to `and` in future lessons!

#3

Thanks! You're Awesome!

#4

The Math.random() method will deliver a number with a value
in the range of 0_(included)_ upontill 0.9999_(1 excluded)_.

As you will have to divide the number range form 0_(inclusive)_ to 0,9999_(so 1 excluded)_
into 3 equal partitions
we have to use an if else-if else statement.
The if else-if else skeleton looks like:

``````    if (conditionA) {
//conditionA is true
} else if (conditionB) {
//conditionA is false
//conditionB is true
} else {     // <=== !! Takes NO condition-statements !!
//conditionA is false
//conditionB is false
}``````

following the Instructions the conditions would be:
1. If computerChoice is between 0 and 0.33, make computerChoice equal to "rock".
( 0 <= computerChoice && computerChoice <= 0.33) which we capture at the IF using
( computerChoice <= 0.33)

1. If computerChoice is between 0.34 and 0.66, make computerChoice equal to "paper".
( 0.33 < computerChoice && computerChoice < 0.67) which we capture at the ELSE IF as
( computerChoice < 0.67 )

2. If computerChoice is between 0.67 and 1, make computerChoice equal to "scissors".
( 0.67 <= computerChoice && computerChoice < 1) , you reached the ELSE level
you can asume that computerChoice is greater equal to 0.67,
the ELSE does NOT take a condition, just write your code.