Syntax Error


#1

I'm sure it is simple but I can't quite figure it out.


#2

Your conditions are incorrect here. Remember that Math.random(); will not generate a number lower than 0, so there is no need to require computerChoice to be greater than 0.

The condition should simply be:

computerChoice <= .33
computerChoice <= .67

**Also, using the word and in your condition is not a valid operator. You will see how to achieve something similar to and in future lessons!


#3

Thanks! You're Awesome!


#4

@jjm363,

The Math.random() method will deliver a number with a value
in the range of 0_(included)_ upontill 0.9999_(1 excluded)_.

As you will have to divide the number range form 0_(inclusive)_ to 0,9999_(so 1 excluded)_
into 3 equal partitions
we have to use an if else-if else statement.
The if else-if else skeleton looks like:

    if (conditionA) {
               //conditionA is true
                //your code 
     } else if (conditionB) {
               //conditionA is false
               //conditionB is true
              //your code 
    } else {     // <=== !! Takes NO condition-statements !!
               //conditionA is false
               //conditionB is false
              //your code 
    }

following the Instructions the conditions would be:
1. If computerChoice is between 0 and 0.33, make computerChoice equal to "rock".
( 0 <= computerChoice && computerChoice <= 0.33) which we capture at the IF using
( computerChoice <= 0.33)

  1. If computerChoice is between 0.34 and 0.66, make computerChoice equal to "paper".
    ( 0.33 < computerChoice && computerChoice < 0.67) which we capture at the ELSE IF as
    ( computerChoice < 0.67 )

  2. If computerChoice is between 0.67 and 1, make computerChoice equal to "scissors".
    ( 0.67 <= computerChoice && computerChoice < 1) , you reached the ELSE level
    you can asume that computerChoice is greater equal to 0.67,
    the ELSE does NOT take a condition, just write your code.