Syntax error


#1

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = "rock";
} else if(computerChoice <= 0.67) {
computerChoice = "paper";
} else {
computerChoice = "scissors";
} console.log("Computer: " + computerChoice);
var compare = function (choice1, choice2) {
if (choice1 === choice2) {
return "The result is a tie!";
}
else if (choice1 === "rock") {

if(choice2 === "scissors") {
return "rock wins";
}
else {
return "paper wins";
}
}
else if (choice1 === "paper") {
if (choice2 === "rock") {
return "paper wins";
}
else {
return "scissors wins"
} }
}
else if (choice1 === "scissors") {
if (choice2 === "rock") {
return "rock wins";
}
else {
return "scissors wins";
}
}
compare (userChoice, computerChoice)
};

I keep getting an error message "SyntaxError: expected expression, got keyword 'else'.

Any clues?


#2

@keleka99,

-1

You have one closing-curly-bracket-] to many in

else if (choice1 === "paper") {
    if (choice2 === "rock") {
        return "paper wins";
    }
    else {
        return "scissors wins"
     }// }
 }

-2

The calling of your compare function

compare (userChoice, computerChoice);

should be OUTSIDE of its definition.....

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )