Syntax Error : What if choice1 is Paper?


#1


https://www.codecademy.com/courses/javascript-beginner-en-Bthev-mskY8/1/3?curriculum_id=506324b3a7dffd00020bf661#

I am getting a syntax error and I don't understand what I'm doing wrong.


var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
	computerChoice = "rock";
} else if(computerChoice <= 0.67) {
	computerChoice = "paper";
} else {
	computerChoice = "scissors";
} console.log("Computer: " + computerChoice);
var compare = function(choice1, choice2) {
    if (choice1 === choice2) {
    return "The result is a tie!"
    }

else if(choice1 ==="rock") {
    
    if(choice2 === "scissors") {
        return "rock wins";
    }
    else {
        return "paper wins";
    }
else if(choice1 === "paper") {
    
    if(choice2 === "rock") {
        return "paper wins"
    }
    else {
        return "scissors wins"
    }
}


#2

You forgot to close your curly braces of you else if.

else if(choice1 ==="rock") {
    if(choice2 === "scissors") {
        return "rock wins";
    }
    else {
        return "paper wins";
    }

And another one, your closing curly braces on your function. just put another closing curly braces in the of your codes