Syntax error on else?


#1

F

 if(computerChoice <= 0.33)
 {
  computerChoice = "rock";
 }
 if else(computerChoice >= 0.34 && <= 0.66)
 {
  computerChoice = "paper";
 }
 else
 {
  computerChoice = "scissors";
 }


#2

@llamacode,

The Math.random() method will deliver a number with a value
in the range of 0_(included)_ upontill 0.9999_(1 excluded)_.

As you will have to divide the number range form 0_(inclusive)_ to 0,9999_(so 1 excluded)_
into 3 equal partitions
we have to use an if else-if else statement.
The if else-if else skeleton looks like:

    if (conditionA) {
               //conditionA is true
                //your code 
     } else if (conditionB) {
               //conditionA is false
               //conditionB is true
              //your code 
    } else {     // <=== !! Takes NO condition-statements !!
               //conditionA is false
               //conditionB is false
              //your code 
    }

following the Instructions the conditions would be:

  1. If computerChoice is between 0 and 0.33, make computerChoice equal to "rock".
    ( 0 <= computerChoice && computerChoice <= 0.33) which we capture at the IF using
    ( computerChoice <= 0.33)

  2. If computerChoice is between 0.34 and 0.66, make computerChoice equal to "paper".
    ( 0.33 < computerChoice && computerChoice < 0.67) which we capture at the ELSE IF as
    ( computerChoice < 0.67 )

  3. If computerChoice is between 0.67 and 1, make computerChoice equal to "scissors".
    ( 0.67 <= computerChoice && computerChoice < 1) , you reached the ELSE level
    you can asume that computerChoice is greater equal to 0.67,
    the ELSE does NOT take a condition, just write your code.


#3

@llamacode
In your logic you also have

+++++range division problem ++++++++++++++++++++++++++++++++
     0         0.33          0.34         0.67        0.9999
     | range1   | lost-range   |  range2    |   range3   |
     |    IF    |      ???     |  ELSE-IF   |    ELSE    |