Syntax error in What if choice1 is paper?


#1


What if choice1 is paper?

Oops, try again. There was a problem with your syntax.


/*var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
	computerChoice = "rock";
} else if(computerChoice <= 0.67) {
	computerChoice = "paper";
} else {
	computerChoice = "scissors";
} console.log("Computer: " + computerChoice);*/

var compare = function (choice1, choice2)
{
   if (choice1 === choice2) 
   {
       return "The result is a tie!";
   }
   else if (choice1 === "paper")
   {
       if (choice2 === "rock")
       {
           return "paper wins";
           }
        else 
        {
            return "scissors wins";
            )
   }
   else if (choice2 === "scissors")
   {
         return "rock wins";
   }
   else 
   {
         return "paper wins";   
   }
};.


#2

@oddlycod
Problem seems to come from here:

No point at the end!

It's not a parentheses, it's a curly bracket.