# Student Becomes the Teacher using for

#1

de code do de work but the answers is not in order.

{'quizzes': [88.0, 40.0, 94.0], 'tests': [75.0, 90.0], 'name': 'Lloyd', 'homework': [90.0, 97.0, 75.0, 92.0]}
('quizzes', [88.0, 40.0, 94.0])
('tests', [75.0, 90.0])
('name', 'Lloyd')
('homework', [90.0, 97.0, 75.0, 92.0])
{'quizzes': [82.0, 83.0, 91.0], 'tests': [89.0, 97.0], 'name': 'Alice', 'homework': [100.0, 92.0, 98.0, 100.0]}
('quizzes', [82.0, 83.0, 91.0])
('tests', [89.0, 97.0])
('name', 'Alice')
('homework', [100.0, 92.0, 98.0, 100.0])
{'quizzes': [0.0, 75.0, 78.0], 'tests': [100.0, 100.0], 'name': 'Tyler', 'homework': [0.0, 87.0, 75.0, 22.0]}
('quizzes', [0.0, 75.0, 78.0])
('tests', [100.0, 100.0])
('name', 'Tyler')
('homework', [0.0, 87.0, 75.0, 22.0])
None

i expect print dictionaris in order.

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [ 88.0, 40.0, 94.0],
"tests": [ 75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

students=[lloyd,alice,tyler]

for x in students:
print x # this print is only for check code
for y  in x.iteritems():
print y``````

#2

dictionary's are unordered in python, because you access by key rather index, there is no reason for dictionary's to be ordered

#3

sorry i suposed dictionaries are in order, thanks for help

#4

Fair assumption, and good you question it.

#5

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