Student Becomes the Teacher : Part of the whole


#1

i dont find a problem with my code still i am getting an error stating :slight_smile: "Oops, try again. get_class_average([alice]) returned 83.8666666667 instead of 91.15 as expected"

check out my code please
lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

Add your function below!

def average(numbers):
total=float(sum(numbers))
return total/len(numbers)

def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
return 0.1*homework + 0.3*quizzes + 0.6*tests

def get_letter_grade(score):
if score >=90:
return "A"
elif score>=80:
return "B"
elif score >=70:
return "C"
elif score >=60:
return "D"
else:
return "F"

def get_class_average(students):
results=[]
results.append(get_average(lloyd))

results.append(get_average(alice))

results.append(get_average(tyler))

return average(results)

#2

Did you remember to loop over students?


#3

Thanks , looping did work :smiley:
Can you tell me what is wrong with my code ?
i mean looping does the same thing right ?


#4

When you use a for- loop, the code gives the output as long as there are items in the thing, that you are looping over.

list = [1, 2, 3]
for x in list:
     print(x)

This code keeps printing items in list as long as there are items, so the output is

 1
 2
 3

And the loop stops running.

But if you just print x, the output is 1 and all the other items don't get printed.
I could also recommend you to append average of all the students to the results, this is faster a lot and looks smarter.


#5

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