Student Becomes the Teacher Exercise 8


#1


https://www.codecademy.com/courses/python-beginner-en-qzsCL/1/4?curriculum_id=4f89dab3d788890003000096

This is saying the get_average for alice is giving the wrong result when I added the last block of code; doesn't make sense though since it didn't give this complaint earlier.


lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!

def get_average(student):
    homework = average(student["homework"])
    quizzes = average(student["quizzes"])
    tests = average(student["tests"])
    total = (homework*0.10) + (quizzes*0.30) + (tests*0.60)
    return total

def average(numbers):
    total = sum(numbers)
    total = float(total)
    return total/(len(numbers))
    
def get_letter_grade(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"
        
get_letter_grade(get_average(lloyd))

def get_class_average(students):
    results = []
    results.append(get_average(lloyd))
    results.append(get_average(alice))
    results.append(get_average(tyler))
    return average(results)


#2

This is what is known as hard coding whereby the result will always be the same, The argument the SCT uses is never considered in the function.


#3

Thanks for the response, but I'm not really sure what you mean


#4

You need to iterate over the parameter (students), not the actual student dictionaries. The function should be able to take a student list of any size.


#6

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