# Student Becomes the Teacher Exercise 8

#1

This is saying the get_average for alice is giving the wrong result when I added the last block of code; doesn't make sense though since it didn't give this complaint earlier.

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
total = (homework*0.10) + (quizzes*0.30) + (tests*0.60)

def average(numbers):
total = sum(numbers)
total = float(total)

if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >= 60:
return "D"
else:
return "F"

def get_class_average(students):
results = []
results.append(get_average(lloyd))
results.append(get_average(alice))
results.append(get_average(tyler))
return average(results)``````

#2

This is what is known as hard coding whereby the result will always be the same, The argument the SCT uses is never considered in the function.

#3

Thanks for the response, but I'm not really sure what you mean

#4

You need to iterate over the parameter (`students`), not the actual student dictionaries. The function should be able to take a student list of any size.

#6

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