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I am having trouble with this function exercise and was wondering if anyone could point me in the right direction.
Oops, try again. by_three(1) returned 'try again' instead of False
I thought that because 9 is divisible by 3, that it would then call the correct function, but instead it returns try again.
number = 9 def cube(number): return number*number*number def by_three(number): if number % 3 == 0: return cube(number) else: return 'try again'