Step 6. What if choice1 is rock?


#1

I have a syntax error of an unexpected token "if"
however I have no idea where I went wrong. I've rewritten this about three times and can't seem to crack it. Any ideas?

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if(computerChoice < 0.34) {
computerChoice = "rock";
} else if(computerChoice <= 0.67) {
computerChoice = "paper";
} else {
computerChoice = "scissors";
} console.log("Computer: " + computerChoice);
var compare = function(choice1, choice2)
if(choice1 === choice2)
{return "The result is a tie!";}
else if(choice1 === "rock")
if(choice2 === "scissors")
{return "rock wins";}
else
{return "paper wins";}
}


#2

@swordrust,

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )

#3

if(choice2 === "scissors")
{
return "rock wins";
}
else
{
return "paper wins";
}

else if(choice1 === "rock")
{
if
and
else go here
}

var compare = function(choice1, choice2)
{
if(choice1 === choice2)
{
return "The result is a tie!";
}
else if goes here
}