The code does exactly what I want it to do, but Code Academy doesn’t like it.
I get this error:
Oops, try again. fizz_count([‘fizz’, ‘buzz’]) returned 3 instead of the correct answer: 1
Here’s what the code does.
It creates a list called x
Then it loops through x making everything lower case
After that it loops through x again checking for “fizz”
The variable count is incremented accordingly
count is printed out to verify it counted the correct number of times fizz appears
#create the list
x = ["Fizz", "Buzz", "FIZZ", "BUZZ", "fIzZ", "bUzZ", "cann"]
print "Before anything:", x
#runs through the list and makes everything lower
#this standardizes the list before checking it for anything
place = 0
for y in x:
x[place] = y.lower()
place += 1
print "Now it's all lower:", x
#takes z as a placeholder for x
#checks if the the list item is "fizz"
#increments count if that is the case
def fizz_count(z):
count = 0
for y in x:
if y == "fizz":
count += 1
print "The number of times fizz occurs is: " + str(count)
return count
fizz_count(x)