[Solved] Code Seems to Work Perfectly, But I Get An Error (Fizz Buzz)


#1

The code does exactly what I want it to do, but Code Academy doesn't like it.

I get this error:

Oops, try again. fizz_count(['fizz', 'buzz']) returned 3 instead of the correct answer: 1

Here's what the code does.

It creates a list called x
Then it loops through x making everything lower case
After that it loops through x again checking for "fizz"
The variable count is incremented accordingly
count is printed out to verify it counted the correct number of times fizz appears

#create the list
x = ["Fizz", "Buzz", "FIZZ", "BUZZ", "fIzZ", "bUzZ", "cann"]
print "Before anything:", x

#runs through the list and makes everything lower
#this standardizes the list before checking it for anything
place = 0
for y in x:
    x[place] = y.lower()
    place += 1
print "Now it's all lower:", x

#takes z as a placeholder for x
#checks if the the list item is "fizz"
#increments count if that is the case
def fizz_count(z):
    count = 0
    for y in x:
        if y == "fizz":
            count += 1
    print "The number of times fizz occurs is: " + str(count)
    return count 
 
fizz_count(x)

#2

Under fizz_count(z)
You have for y in x.
Think about x and z.


#3

sunnuva....thanks man.