# Slip and Slide - why the n-1

#1

it works because I saw the solution on a different topic, but those do not explain why the n -1.

Can someone drop their 2 cents?

``````def flip_bit(number, n):

return bin(result)

print flip_bit(0b111, 3)``````

#2

It's not immediately evident but, `n - 1` converts a position number (from the right) to a degree. Were we to desire a flip of the first bit (n == 1), we would not want to shift at all, hence `n-1`. This logic is consistent universally no matter how many bits.

should return `0b11`.

#4

I think this exercise can use some more explanation. I understand that it's rarely used but it's just for the sake of learning something that exists in a language

#5

That's where extra reading comes in. The author has here only introduced the concepts; it is up to us as self-learners to follow through with our own research, study and practice. This site is not a be-all-to-end-all, but just a beginning. Some will continue on, others will quit. Not our responsibility.

#6

Yes , true but I don't mean the idea I mean the instructions of the exercise itself

#7

Not going to happen, at least not in this iteration of the courseware. A newer version of this course is slated to appear in the new year. We'll have to see if anything changes come then.

#8

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