I am trying to avoid an error when the user inputs a string/letter as a column or a row.
However I cannot seem to get the proper type to set the if…
Removing the int() sets the input types as “Unicode” and letting the int() will generate an error when inputting a letter.
How can I achieve this?
Here’s my code right now.
The type(guess_row) and col was written to test out the different type results
from random import randint board =  for x in range(0, 5): board.append(["O"] * 5) def print_board(board): for row in board: print " ".join(row) print_board(board) def random_row(board): return randint(0, len(board) - 1) def random_col(board): return randint(0, len(board) - 1) ship_row = random_row(board) ship_col = random_col(board) print ship_row print ship_col guess_row = int(raw_input("Guess Row: ")) guess_col = int(raw_input("Guess Col: ")) print guess_row print guess_col print type(guess_row) print type(guess_col) # Write your code below! if guess_row == ship_row and guess_col == ship_col: print "You win, I guess" elif type(guess_row) != int or type(guess_col) != int: print "C'mon. You need to enter numbers." elif board[guess_row][guess_col] == "X": print "You guessed that one already." else: if guess_row not in range(5) or \ guess_col not in range(5): print "Oops, that's not even in the ocean." else: print "You missed the battleship!" board[guess_row][guess_col] = "X" print_board(board)