#1

Problem with the results in students marks averaging by using dictionary...i got the result 83.8666666667
but the server says "Oops, try again. get_class_average([alice]) returned 85.6875 instead of 91.15 as expected "

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers=[]):
total=sum(numbers)
result=float(total)/len(numbers)
return result
def get_average(student):
homework=average(student["homework"])
quizzes=average(student["quizzes"])
tests=average(student["tests"])
return homework*0.1 + quizzes*0.3 + tests*0.6
if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >=70 :
return "C"
elif score >= 60:
return "D"
else:
return "F"

def get_class_average(students):
for stu in students:
results.append(get_average(stu))
return average(results)

results = []
students= [lloyd,alice,tyler]
print get_class_average(students)``````

#2

because `results` is not defined inside the function, calling the function multiply times will mean results will accumulate too much data, as we can see:

``````print get_class_average(students)
print get_class_average([alice]) # wrong result because results accumulate``````

#3

Thankyou so much sir, I will declare the results variable inside the
function.

#4

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