Server says incorrect answer


#1

Problem with the results in students marks averaging by using dictionary...i got the result 83.8666666667
but the server says "Oops, try again. get_class_average([alice]) returned 85.6875 instead of 91.15 as expected "

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!
def average(numbers=[]):
    total=sum(numbers)
    result=float(total)/len(numbers)
    return result
def get_average(student):
    homework=average(student["homework"])
    quizzes=average(student["quizzes"])
    tests=average(student["tests"])
    return homework*0.1 + quizzes*0.3 + tests*0.6
def get_letter_grade(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >=70 :
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

def get_class_average(students):
    for stu in students:
        results.append(get_average(stu))
    return average(results)
    
results = []
students= [lloyd,alice,tyler]
print get_class_average(students)

#2

because results is not defined inside the function, calling the function multiply times will mean results will accumulate too much data, as we can see:

print get_class_average(students)
print get_class_average([alice]) # wrong result because results accumulate

#3

Thankyou so much sir, I will declare the results variable inside the
function.


#4

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