All I have to say is that I honestly don’t know what to do on question 3 " Now, let’s format val to have our function return a percentage. We want to:
val by 100
'%'"They want a formatted string. I don’t know if this is python 2 or 3 though.
in python 2 you might do something like: '{:.1f}%'.format(val*100)
in python 3 you can do something like '{}%'.format(val*100) (can you also do this in 2? I’m not sure) also I omitted the rounding in this example… left as an exercise… i’m not lazy… (yes I am)
Here’s a nice article (that also includes f-strings… which are just another way to do a very similar thing): https://realpython.com/python-f-strings/
Also, if you need to round a number, you can use the round() function.
number=3.44
rounded_num=round(number,1)
print(rounded_num)
>>>3.4
IDK if this is supported in Python 2.
Im in python3 no worries
‘{}%’.format(val*100)
This isnt working im not sure why. (I’m in python 3 btw) where do I add this, after the return?
You can
formatted_result = '{}%'.format(val*100)
return formatted_result
or
return '{}%'.format(val*100)
all assuming you have a val with a value.
We don’t need to do any rounding if the return value is a formatted string.
return f"{100 * val:.1f}"
The rounding is done for us, and not like round(), but the true up on 5, down on 4 type of rounding.
it didnt work idk why
its not working hmmmm
can you copy and paste what you put? (make sure to format it with the </> button).
Above I left off the %. Once that is added it passes for me and displays, 7.5%.
<rate_of_return = 0.075
def display_as_percentage(val):
return ‘{}%’.format(val*100)>
Round the result to 1 decimal place
Where is your rounding?
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