Sending a letter - issues


#1

Ok folks - this is my code:

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}


def average(numbers):
    total = sum(numbers)
    total = float(total) / len(numbers)
    return total

def get_average(student):
    homework = average(student["homework"])
    quizzes= average(student["quizzes"])
    tests = average(student["tests"])
    return 0.1 * homework + 0.3 * quizzes + 0.6 * tests 
    
def get_letter_grade(score):
    float(score)
    if score >= 0.9: 
        return "A"
    elif score >= 0.8:
        return "B"
    elif score >= 0.7:
        return "C"
    elif score >= 0.6:
        return "D"
    else:
        return "F"
        
print get_letter_grade(get_average(lloyd))

Oops, try again.
    get_letter_grade(89) returned 'A' instead of 'B' as expected.

I cant seem to put my finger on it - somebody help.


#2

You are supposed to use normal integer values not strings,

if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

and not,

    if score >= 0.9: 
        return "A"
    elif score >= 0.8:
        return "B"
    elif score >= 0.7:
        return "C"
    elif score >= 0.6:
        return "D"
    else:
        return "F"

and remove this line,


#3

thanks - i completely overlooked that. Much appreciated.


#4

you're welcome :slight_smile:


#5

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